abc172_c - Tsundoku
28 Jan 2021 — Tags: None
Click to show code.
using namespace std;
using ll = long long;
int const NMAX = 2e5 + 11;
int n, m;
ll k, pa[NMAX], pb[NMAX];
int main(void)
{
int ai, bi;
cin >> n >> m >> k;
for (int i = 1; i <= n; ++i)
cin >> ai, pa[i] = ai + pa[i - 1];
for (int i = 1; i <= m; ++i)
cin >> bi, pb[i] = bi + pb[i - 1];
int ans = 0, j;
for (int i = 0; i <= n; ++i)
{
if (k - pa[i] < 0)
break;
auto match = prev(upper_bound(pb + 1, pb + m + 1, k - pa[i]));
j = distance(pb, match);
ans = max(ans, i + j);
}
cout << ans << endl;
return 0;
}