1341A - Nastya And Rice
28 Jan 2021 — Tags: None
Click to show code.
using namespace std;
using ll = long long;
int main(void)
{
int t, n, a, b, c, d;
ll minsum, maxsum;
bool ans;
cin >> t;
while (t--)
{
cin >> n >> a >> b >> c >> d;
minsum = n * (a - b);
maxsum = n * (a + b);
ans = ((minsum) > (c + d)) or (maxsum < (c - d));
cout << (not ans ? "Yes" : "No") << endl;
}
return 0;
}