1135 - Distance Queries
28 Jan 2021 — Tags: None
Click to show code.
using namespace std;
using ll = long long;
using ii = pair<int, int>;
using vi = vector<int>;
template <typename InputIterator,
typename T = typename iterator_traits<InputIterator>::value_type>
void read_n(InputIterator it, int n)
{
copy_n(istream_iterator<T>(cin), n, it);
}
template <typename InputIterator,
typename T = typename iterator_traits<InputIterator>::value_type>
void write(InputIterator first, InputIterator last, const char *delim = "\n")
{
copy(first, last, ostream_iterator<T>(cout, delim));
}
int const NMAX = 2e5 + 11;
int const LMAX = 20;
int n, timer, tin[NMAX], tout[NMAX], up[NMAX][LMAX], depth[NMAX];
vi g[NMAX];
void dfs(int u, int p)
{
tin[u] = ++timer;
up[u][0] = p;
for (int i = 1; i < LMAX; ++i)
{
up[u][i] = up[up[u][i - 1]][i - 1];
}
for (int v : g[u])
{
if (v != p)
{
depth[v] = depth[u] + 1;
dfs(v, u);
}
}
tout[u] = ++timer;
}
bool is_ancestor(int u, int v)
{
return tin[u] <= tin[v] and tout[u] >= tout[v];
}
int lca(int u, int v)
{
if (is_ancestor(u, v))
return u;
if (is_ancestor(v, u))
return v;
for (int i = LMAX - 1; i >= 0; --i)
{
if (!is_ancestor(up[u][i], v))
u = up[u][i];
}
return up[u][0];
}
int main(void)
{
ios::sync_with_stdio(false), cin.tie(NULL);
int q;
cin >> n >> q;
for (int i = 0; i < n - 1; ++i)
{
int u, v;
cin >> u >> v;
g[u].push_back(v);
g[v].push_back(u);
}
dfs(1, 1);
while (q--)
{
int u, v;
cin >> u >> v;
cout << depth[u] + depth[v] - 2 * depth[lca(u, v)] << endl;
}
return 0;
}