1130 - Tree Matching
28 Jan 2021 — Tags: None
Click to show code.
using namespace std;
using ll = long long;
using ii = pair<int, int>;
using vi = vector<int>;
template <typename InputIterator,
typename T = typename iterator_traits<InputIterator>::value_type>
void read_n(InputIterator it, int n)
{
copy_n(istream_iterator<T>(cin), n, it);
}
template <typename InputIterator,
typename T = typename iterator_traits<InputIterator>::value_type>
void write(InputIterator first, InputIterator last, const char *delim = "\n")
{
copy(first, last, ostream_iterator<T>(cout, delim));
}
int const NMAX = 2e5 + 11;
int n, dp1[NMAX], dp2[NMAX];
vi g[NMAX];
void solve(int u, int p = 0)
{
for (auto v : g[u])
{
if (v == p)
continue;
solve(v, u);
dp2[u] += max(dp1[v], dp2[v]);
}
for (auto v : g[u])
{
if (v == p)
continue;
auto v_choice = max(dp1[v], dp2[v]);
dp1[u] = max(dp1[u], 1 + dp2[u] - v_choice + dp2[v]);
}
}
int main(void)
{
ios::sync_with_stdio(false), cin.tie(NULL);
cin >> n;
for (int i = 0; i < n - 1; ++i)
{
int u, v;
cin >> u >> v;
g[u].push_back(v);
g[v].push_back(u);
}
int root = 1;
solve(root);
cout << max(dp1[root], dp2[root]) << endl;
return 0;
}