1083 - Missing Number
28 Jan 2021 — Tags: None
Click to show code.
using namespace std;
int main(void)
{
int n, x;
cin >> n;
vector<bool> is_present(n + 1, false);
for (int i = 0; i < n - 1; ++i)
{
cin >> x;
is_present[x] = true;
}
for (int i = 1; i <= n; ++i)
if (not is_present[i])
cout << i << endl;
return 0;
}