1475D - Cleaning The Phone
25 Jan 2021 — Tags: binary_search,sortings — URLTime complexity: $O(n \log{n})$
Memory complexity: $O(n)$
Click to show code.
using namespace std;
using ll = long long;
using ii = pair<int, int>;
using vi = vector<int>;
int solve(vi a, vi b, int m)
{
int n = (int)(a).size();
vector<ll> acc[2];
acc[0] = {0}, acc[1] = {0};
for (int i = 0; i < n; ++i)
acc[b[i] - 1].push_back(a[i]);
for (int i = 0; i < 2; ++i)
{
auto start = begin(acc[i]) + 1;
sort(start, end(acc[i]), greater<int>());
partial_sum(start, end(acc[i]), start);
}
ll const INF = 1e15;
ll ans = INF;
int n1 = acc[0].size();
for (int i = 0; i < n1; ++i)
{
auto it = lower_bound(begin(acc[1]), end(acc[1]), max(0LL, m - acc[0][i]));
if (it != acc[1].end())
{
int j = distance(begin(acc[1]), it);
ans = min(ans, i + 2LL * j);
}
}
return ans == INF ? -1 : ans;
}
int main(void)
{
ios::sync_with_stdio(false), cin.tie(NULL);
int t;
cin >> t;
while (t--)
{
int n, m;
cin >> n >> m;
vi a(n), b(n);
for (auto &ai : a)
cin >> ai;
for (auto &bi : b)
cin >> bi;
cout << solve(a, b, m) << endl;
}
return 0;
}